-1.02x^2+7.3x+2=0

Solution for -1.02x^2+7.3x+2=0 equation:

-1.02x^2+7.3x+2=0

a = -1.02; b = 7.3; c = +2;
Δ = b2-4ac
Δ = 7.32-4·(-1.02)·2
Δ = 61.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.3)-\sqrt{61.45}}{2*-1.02}=\frac{-7.3-\sqrt{61.45}}{-2.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.3)+\sqrt{61.45}}{2*-1.02}=\frac{-7.3+\sqrt{61.45}}{-2.04}
$